Learning xls-Poisson / Exponential Distributions (2.c.2)

PDEM200

Member
Hi David,
I was reviewing the xls related to the Poisson vs Exponential Distribution and was hoping that you could provide some additional details about the interpretation using the second column data (Lambda =4).

On the Poisson: My understanding is that given a lambda of 4, the probability of 2 events occuring in a day is 14.7%.

It is on the Exponential that I would appreciate some clarification:

1) Is it correct to say that there is a 13.5 % probability that the next 2 events ( x value from Poisson) will take more thanthan 12 hrs to occur (eg. Y> t)?

Similarly,

2) There is an 86.5% probability that the next 2 events will occur within the next 12 hrs?

Thank you
 
Hi Paul

(sorry for delay responding...)
You are correct about the Poisson.
However, the Exponential here refers to the Probability that the *next* single event (just one) will occur before/after a period time. In the second column, the first input assumption is 4: lambda = average of 4 events per day
Then under exponential, the input (H) = 12 so we are asking:
"What is the probability a single event will occur within 12 hours"
and given that the average number of events during the H-period = 2
(i.e., 4 per day = average of 2 per 12-hour period)
this imples a probability of 13.5% [i.e., EXP(-2)] that next even occurs *after* 12 hours and therefore 1-13.5% = 86.5% that the next (single) event occurs within/before the next 12 hours.

So, the P[Y<t], CDF = 86.5% means the Probability [time to next event <= 12 hours]

Thanks, David
 
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