How is the probability of exceeding a barrier (minimum % + or - return) in a minimum number of time steps, from today's date and stock price calculated?
I'd personally use a bootstrap simulation. Find a time period that you feel is similar to the one in the time frame of interest - then take random draws of share price returns from that period and run a simulation.of how the share price could move. If you hit the barrier - then add 1 to a variable that counts number of successes. If not - don't add anything. Repeat this exercise a couple of million times - and then divide the total number of successes by the number of iterations you ran. The output will give you an stimate of the probability you are looking for. / Mac
In the context of a binomial, I may be underthinking (under-encapsulating) this but it seems straightforward. Let S = current asset price; u = up jump magnitude; and h = barrier up, then:
S*u^n = H; i.e., barrier H is reached in minimum steps (n) if the up-magnitude compounds (n) times, so this is just jumping up the tree as quickly as possible
Then n = log[base u](H/S) is the minimum number of steps
The probability is then p^n; i.e., the probability of (n) consecutive up jumps.
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