Hi David,
Need your help on this question given below, this is taken from the 2008 practice set.
Q Consider an asset worth USD 1 million whose 95th percentile VaR is USD 100,000 (computed using the
parametric method assuming the normal distribution). Suppose the bid-ask spread on the asset has a
mean of USD 0.10 and a standard deviation of USD 0.30. What is the 95th percentile liquidity adjusted
VaR assuming the market risk VaR and the liquidity risk piece are uncorrelated?
a. USD 200,000
b. USD 344,000
c. USD 444,000
d. USD 688,000
Explanation: If the VaR is USD100,000, the liquidity piece can be estimated from the mean and std
dev of the spread as V (μ - 1.96σ) = USD1,000,000 (USD0.10 - (1.96)(USD0.30)) = USD344,000
With no correlation to the market risk piece, we add to get (b).
Reference:
Christopher L. Culp, he Risk Management Process: Business Strategy and Tactics (Hoboken: John Wiley &
Sons, Inc, 2001)., Chapter 17 – Identifying, Measuring, and Monitoring Liquidity Risk
How can we arrive at the ans given the formula that we learned to add the 1/2 spread to the absolute VAR. I could not understand the formula used in the explanation and also if you notice 1.96 is used at 95th percentile (two tailed ?).. Pls advice, appreciate your guidance on this..thanks
Need your help on this question given below, this is taken from the 2008 practice set.
Q Consider an asset worth USD 1 million whose 95th percentile VaR is USD 100,000 (computed using the
parametric method assuming the normal distribution). Suppose the bid-ask spread on the asset has a
mean of USD 0.10 and a standard deviation of USD 0.30. What is the 95th percentile liquidity adjusted
VaR assuming the market risk VaR and the liquidity risk piece are uncorrelated?
a. USD 200,000
b. USD 344,000
c. USD 444,000
d. USD 688,000
Explanation: If the VaR is USD100,000, the liquidity piece can be estimated from the mean and std
dev of the spread as V (μ - 1.96σ) = USD1,000,000 (USD0.10 - (1.96)(USD0.30)) = USD344,000
With no correlation to the market risk piece, we add to get (b).
Reference:
Christopher L. Culp, he Risk Management Process: Business Strategy and Tactics (Hoboken: John Wiley &
Sons, Inc, 2001)., Chapter 17 – Identifying, Measuring, and Monitoring Liquidity Risk
How can we arrive at the ans given the formula that we learned to add the 1/2 spread to the absolute VAR. I could not understand the formula used in the explanation and also if you notice 1.96 is used at 95th percentile (two tailed ?).. Pls advice, appreciate your guidance on this..thanks