Hi @David Harper CFA FRM CIPM
This is probably a trivial question.
In the notes to Grinold (and in the reading itself) about Alpha scaling it states:
...the original alphas have a standard deviation of 2.00 percent and the modified alphas have a standard deviation of 0.57 percent. This implies that the constraints in this example effectively shrank the IC by 62 percent, a significant reduction.
using Alpha = Vol * IC * Score how do we get to IC being reduced by 62% in the above? Score we assume is 0 so I tried to scale the average alpha of the original and modified and i got 72% reduction but I have a feeling I'm reading this incorrectly!.
Thanks
This is probably a trivial question.
In the notes to Grinold (and in the reading itself) about Alpha scaling it states:
...the original alphas have a standard deviation of 2.00 percent and the modified alphas have a standard deviation of 0.57 percent. This implies that the constraints in this example effectively shrank the IC by 62 percent, a significant reduction.
using Alpha = Vol * IC * Score how do we get to IC being reduced by 62% in the above? Score we assume is 0 so I tried to scale the average alpha of the original and modified and i got 72% reduction but I have a feeling I'm reading this incorrectly!.
Thanks