wrongsaidfred
Member
Hi David,
I saw a great article you wrote about how effective convexity can be defined as having a 2 in the denominator, in which case the convexity adjustment is just C*(delta y)^2, or without a 2 in the denominator and then the convexity adjustment would be 0.5*C*(delta y)^2.
Tuckman uses the latter form of the adjustment in chapter 5. Does this mean that this is the equation we should use on the exam and that we should assume that if we are given convexity it is being calculated using the formula without the 2 in the denominator?
Thanks,
Mike
I saw a great article you wrote about how effective convexity can be defined as having a 2 in the denominator, in which case the convexity adjustment is just C*(delta y)^2, or without a 2 in the denominator and then the convexity adjustment would be 0.5*C*(delta y)^2.
Tuckman uses the latter form of the adjustment in chapter 5. Does this mean that this is the equation we should use on the exam and that we should assume that if we are given convexity it is being calculated using the formula without the 2 in the denominator?
Thanks,
Mike