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    Exam Feedback May 2016 Part 2 Exam Feedback

    I can't understand a 1 at the same place in my case... :D..but anyways a pass is a pass.Congrats!
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Thanks a lot bro!Wishing you all the best as well!So we did survive it eventually...:p:p
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Passed!!! :):) Thanks a lot David for helping cross this wall of fire...
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Hi Ajay,apparently the reverse is true for '11 and '12 and the two %ages have been almost identical in '10 and '14,if the chart at the top of the page is assumed as accurate.So other factors are also at play for sure..
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Kavita honestly it seems like this depends on the shape of the distribution of marks.If the tail is thin(a distance of few marks from mean covers more %age of candidates than normal) then in the interest of fairness,GARP would want to pass this larger set of people because they're close in terms...
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Hahahahahahahahaha......
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Wow so if we look at it,55 odd pass %age is more of a downside..generally this has touched 60% throughout..now the question is whether pass %age varies directly or inversely with difficulty level....
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    Exam Feedback May 2016 Part 2 Exam Feedback

    The answer is NO and 50% :-)
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    Exam Feedback May 2016 Part 2 Exam Feedback

    @Mkain:--Maybe individual quartiles also have a mean of 2 and std deviation of (+/-) 1.... :)
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Hehehehehe....yeah,anyways people don't write XYZ,FRM(4th quartiler) in their resume do they? :D....not to say I want that for any of us but hey, a ",FRM" is a ",FRM"... :-)
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Difficult people...though I would have wanted a 1/1/1/1/1,will be dancing all the way to the bar if I pass :p
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Mate infact now if they put up a simple paper that'll be an anamoly.I prepared for part 1 via a different institute(non BT,non shwescher) and could crack 75%+ in 2.5 hrs..but part 1 last year was a horror story...could attempt 89/100 only after consuming the whole 4 hours but ended up passing...
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Any group discounts? :-)
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Yeah so I think I do have a chance at failing this one,but will put the significance level at 2.5% :-)
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Hehe couldn't resist after months of practicing fat/thin tails,extreme values,time varying volatilities and other such arcane topics :)
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Guys,since we're talking of FRM P2 here,let's appreciate the fact that the marks obtained will follow a probability distribution with thin tails(very few will nail it out and out or flunk horribly).There's no linear logic that says 75%==gold medal and hence 60%==pass.What if few dozen people get...
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    Exam Feedback May 2016 Part 2 Exam Feedback

    One aspect is the number of questions outside of all study packages(5-6 atleast),where even the most prepared folks would need to half-guess.Plus not may would have genuinely attempted 77-80.And even if we take the absentees out(not sure if that's valid),still more than half would be passing.So...
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Even the top most scorer could have only attempted 80,and with so many close calls,would easily get 15 wrong so 65-60 would be a top 5% score and not any lower.Now we have to consider the fact that many people would have have genuinely attempted 65-70 odd to begin with,and also that there would...
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    Exam Feedback May 2016 Part 2 Exam Feedback

    Lol that was funny...50/80 is a sure shot for this test I suppose.What do you guys think of the cutoff?
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    P2.T6.304. Single-factor credit risk model

    Hi David, A silly doubt on concept actually. From the formula sheet page 55, 1)Since return= beta*m +sqrt(1-beta^2)*epsilon,I am assuming that whether (k-return)>or<0 will decide default or no default.So not sure why epsilon<k-beta*m denotes default.Should'nt this be the opposite? 2)Again if...
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