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  1. B

    P1.T2.406. Distributions II

    406.1. = d Ho=<0.01 vs Ha>0.01 - one tailed test X^2 at 14 df and 5% critical value is 23.68. So, reject Ho if chi-squared statistics is > 23.68 critical value. X^2 statistics = (Q^2/Q0^2)*(n-1)df=0. =(0.0196/0.01)*14=27.44 Thus, chi-squared statistics 27.44 is greater than 23.68 and Ho is...
  2. B

    P1.T2.406. Distributions II

    a,c,a
  3. B

    P1.T3.405. Forward and futures review

    c.a.b
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