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I get it. I think you meant "but you want 0.082% - 0.60% = 0.00082 - 0.006^2 = 0.000784" Thanks

304.1 Can someone explain why we can't employ the E[X^2] - E[X]^2 = Var[X] rule here? The solution describes that E[X^2] = 0.820%, and E[X] = 0.600% 0.820 - .6^2 = -.278 which obviously can't be right. Thanks

Can you explain to me why in 300.2, I use .05 for p, while in 300.3, I use .95. Both ask for 95% VaR. Am I missing some nuance in wording or an important concept?

Can someone briefly explain the theory behind solving for x and how thats related to the inverse CDF?